〚AMC8-c11-e7改〛⭐⭐⭐⭐💯

题目

How many triples of three positive integers(x,y,z) have theproduct of 8640? (A)20 (B)24 (C)27 (D)30 (E)21 归属：

解答

1. 分解：$8640=8\times 54\times 20=8\times 6\times 9\times 2\times 10=2^6\times 3^3\times 5$

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